Integrals...(4)

Calculus Level 4

Let y(x)=π216x2cos(x)cos(θ)1+sin2(θ)dθy(x)=\int_{\frac{\pi^2}{16}}^{x^2}\frac{\cos(x) \cos(\sqrt{\theta})}{1+\sin^2(\sqrt{\theta})}d\theta

Value of dydx\frac{dy}{dx} at x=πx=\pi can be expressed as nπn\pi find find 4n+14n+1

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