Squares of Trigonometric Ratios (2)

Calculus Level 4

0π/2dx16sin2x+9cos2x=? \large \displaystyle \int_{0}^{\pi/2}\dfrac{dx}{16 \sin^2x + 9 \cos^2 x}= \, ?

Give your answer to 3 decimal places.

For your final step, you may use the approximation π=227\pi = \dfrac{22}{7}.

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