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∫01(∏k=1n(x+k))(∑r=1n1x+r)dx\int^{1}_{0}\left(\prod^{n}_{k=1}(x+k)\right)\left(\sum^{n}_{r=1}\dfrac{1}{x+r}\right) dx∫01(k=1∏n(x+k))(r=1∑nx+r1)dx
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