# Integration At Its Best

Calculus Level 5

$\displaystyle \left( \int _{ 0 }^{ 1 }{ \dfrac { { x }^{ 2 }\cdot dx }{ \sqrt { 1-{ x }^{ 4 } } } } \right) \cdot \left( \int _{ 0 }^{ 1 }{ \dfrac { dx }{ \sqrt { 1+{ x }^{ 4 } } } } \right)$

The value of the expression above can be expressed in the form of $$\dfrac { \pi }{ \beta \sqrt { \gamma } } .$$ Find $${ \beta }^{ \gamma }.$$

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