# Interesting triples!Hmmmm!

Level pending

If $$a$$,$$b$$ and $$c$$ are real numbers such that :

$$\dfrac{a-c}{b+c}+\dfrac{b-a}{c+a}+\dfrac{c-b}{a+b}=1$$ then what is the value of :$$\dfrac{a+b}{b+c}+\dfrac{b+c}{c+a}+\dfrac{c+a}{a+b}=$$?

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