If \(\alpha\), \(\beta\), \(\gamma\) and \(\delta\) are the eccentric angles of four concyclic points on the ellipse \(\displaystyle\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\). Then \(\alpha + \beta + \gamma + \delta = ?\)

If general solution of the answer in \(n\) is of the form \((m\cdot n+k)\times\left(\text{any known constant}\right)\), give your answer as \((m+k)\times\left(\text{the known constant}\right)\)

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