Let \(x_1,x_2,x_2,.....,x_n\) be \(n\) real values of \(p\) for which the least value of \(4x^2-4px+p^2-2p+2\) on the interval \(0 \leq x \leq 2\) is equal to 3. Find the value of

\[\dfrac{x_1+x_2+x_3+....+x_n}{n}.\]

**Note:** Answer to 3 decimal points.

×

Problem Loading...

Note Loading...

Set Loading...