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If f:R→Rf: \mathbb {R \to R}f:R→R, f(x)=x+sinxf(x)=x+\sin xf(x)=x+sinx, then find the value of
∫0πf−1(x) dx\large \int_{0}^{\pi} f^{-1}(x) \ dx∫0πf−1(x) dx
Note : f−1(x)f^{-1}(x)f−1(x) denotes the inverse function of f(x)f(x)f(x).
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