Iodine Mapping

Chemistry Level 3

\(\ce{Propyne}\) is reacted in the following way:

  • 1) \(\ce{NaNH_2}\)
  • 2) \(\ce{BrCH_3}\)
  • 3) 2 moles of \(\ce{HI}\)

The major product will be \(\ce{\underline{_},\underline{_}~-~diiodo~butane}\). Fill in the blanked positions of the iodines.

Use IUPAC numbering protocol to formulate your answer.

David's Organic Chemistry Set

David's Physical Chemistry Set


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