# Ionic Equilibrium - 1

Chemistry Level 3

What is the $$\text{pH}$$ of the resultant solution formed by adding these 5 weak acids?

Here $$c$$ is the Concentration and $$k_a$$ is the acid dissociation constant.

Acid 1 : $${c}_{1} = 0.1999 N$$ , $${k}_{\text {a1}} = 2.036 × {10}^{-15}$$

Acid 2 : $${c}_{2} = 0.02367 N$$ , $${k}_{\text {a2}} = 5.0093× {10}^{-15}$$

Acid 3 : $${c}_{3} = 0.5678 N$$ , $${k}_{\text {a3}} = 3.9925 × {10}^{-16}$$

Acid 4 : $${c}_{4} = 0.09826 N$$ , $${k}_{\text {a4}} = 6.5762 × {10}^{-16}$$

Acid 5 : $${c}_{5} = 6.753 N$$ , $${k}_{\text {a5}} = 0.7036 × {10}^{-15}$$

Enter your answer as $$[ \text {pH} ]$$ , where [ ] is greatest integer function.

Original!

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