Is it Linear?

Calculus Level 4

$y' \times \big(x^2 y^3 + xy \big) = 1$

The general solution of the differential equation above is $\text{\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_}.$

\frac{1}{x} = 1 - y^2 + ce^{\frac{-y^2}{2}}

\frac{1}{x} = 2 - y^2 + ce^{\frac{-y^2}{2}}

\frac{2}{x} = 1 - y^2 + ce^{\frac{-y^2}{2}}

\frac{2}{x} = 2 - y^2 + ce^{\frac{-y^2}{2}}