Forgot password? New user? Sign up
Existing user? Log in
y′×(x2y3+xy)=1 y' \times \big(x^2 y^3 + xy \big) = 1y′×(x2y3+xy)=1
The general solution of the differential equation above is ____________________.\text{\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_}.____________________.
Problem Loading...
Note Loading...
Set Loading...