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6x3−3x2−6x−4=0\large 6x^3-3x^2-6x-4=06x3−3x2−6x−4=0
The real root to the equation above can be written in the form a3+b3+1c\large \dfrac{\sqrt[3]{a}+\sqrt[3]{b}+1}{c}c3a+3b+1, where aaa, bbb and ccc are positive integers.
Find a+b+ca+b+ca+b+c.
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