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1+2+3+4+5=151 + 2 + 3 + 4 + 5 = 15 1+2+3+4+5=15 is divisible by 5. 7+8+9+10+11=457 + 8 + 9 + 10 + 11 = 457+8+9+10+11=45 is divisible by 5. 23+24+25+26+27=12523 + 24 + 25 + 26 + 27 = 12523+24+25+26+27=125 is divisible by 5.
Is it true that the sum of any 5 consecutive integers is divisible by 5?
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