Is there a quicker way?

Algebra Level 4

\[ \dfrac{1^2}{1^2-24+288} + \dfrac{2^2}{2^2-48+288} + \cdots + \dfrac{23^2}{23^2-23(24)+288} + \dfrac{24^2}{24^2-24(24)+288} = \, ? \]

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