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If cos(θ)=cos(α)cos(β)\cos(\theta)=\cos(\alpha)\cos(\beta)cos(θ)=cos(α)cos(β) and tan(θ+α2)tan(θ−α2)=f(β)\tan(\frac{\theta+\alpha}{2})\tan(\frac{\theta-\alpha}{2})=f(\beta)tan(2θ+α)tan(2θ−α)=f(β).
then find f(π6)f(\frac{\pi}{6})f(6π)
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