# Is this year 2025? I don't think so!

Calculus Level 4

Find $$\left\lfloor \sum _{ n=1 }^{ 2025 }{ \sqrt { \frac { 1 }{ n } } } \right\rfloor$$.

Bonus : Can you generalize for all perfect square $$n$$ which are greater or equal than $$1$$?

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