# Stretching = Translation

**Algebra**Level 2

\[\alpha f(x) = f(x + \alpha) \]

Given that \( \alpha \) is a real number greater than 1, does a non-constant function \(f \colon \mathbb{R} \to \mathbb{R} \) exist that satisfies the above functional equation for all \( x \)?

**Bonus**

If you think the answer is yes, then find all functions that satisfy the given equation.

If you think the answer is no, then prove it.

What happens when \( 0 < \alpha < 1\)? What happens when \( \alpha < 0 \)?