It is simpler than it looks!
Calculus
Level
5
\[\sum _{ n=1 }^{ \infty }{ \frac { 1 }{ { n }^{ 2 }\left( \begin{matrix} 2n \\ n \end{matrix} \right) } } =\frac { A }{ B } \zeta \left( C \right) \]
In the equation above, \(A,B,C\) are positive integers such that \(A\) and \(B\) are co-prime.
Find \(A+B+C.\)
by
Aditya Kumar