It isn't as complicated as it looks

Algebra Level 4

\[\large \frac{1}{(1-x)(1-y)(1-z)}+\frac{1}{(1+x)(1+y)(1+z)} \] For \(-1<x,y,z<1\), let \(t\) denote the minimum value of the above expression and \(u\) be the sum of \(x,y,z\) when the equality holds, find \((3t)^{u}+4\).

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