It only looks simple!

Consider a square loop of side length \(l\) and each side having mass \(m\) carrying a current \(i\) placed in the plane of an infinitely large wire at a distance \(d\) from it. The wire carries a current \(I\).

The axis of the loop shown is fixed. Now, we rotate the loop by a small angle. Find the time period of oscillations of the loop in Seconds . Below is the figure and details :

\(l = 10 \text{cm}, d = 10 \text{cm}, I = 50 A, i = 4A, m = 30 g \)

Details and assumptions

The answer to this physics problem is a real number.


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