# It should be double

I have a biased coin, which means that the probability of getting heads is not equal to the probability of getting tails.

If the probability of getting $$2$$ heads and $$1$$ tail in $$3$$ tosses is $$\dfrac{1}{6}$$, then what is the probability of getting $$4$$ heads and $$2$$ tails in $$6$$ tosses?

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