It's almost trivial!

Calculus Level 3

(1+1x)x+1=(1+11999)1999\large \left ( 1 + \dfrac{1}{x} \right )^{x+1} = \left ( 1 + \dfrac{1}{1999} \right )^{1999}

Find the sum of all real xx such that the above equation is true.

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