\[\int _{ 0 }^{ \pi }{ \sum _{ k=0 }^{ \infty }{ \frac { \sin { \left( x\left( 2k+1 \right) \right) } }{ 2k+1 } } } dx= \frac{ \pi ^a } { b },\]

where \( a\) and \(b\) are integers. Find \(10a+b\).

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