Its Not that easy!!

A block of mass 2 kg2 \ \text{kg} slides down an inclined plane of inclination 3030^{\circ}. The coefficient of friction between the block and plane is 0.50.5. The magnitude of contact force between block and plane can be expressed in the form a N\sqrt{a} \ \text{N} where aa is a positive nonsquare integer.

Find the sum of digits in aa.

Assume the plane is fixed. Take g=10 ms2g = 10 \ \text{ms}^{-2}.

This Question Is Inspired From An Old JEE Question

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