It's still 2014!

Algebra Level 5

Let \(\alpha\) and \(\beta\) be the roots of \(x^2-6x-2=0\), with \(\alpha >\beta\). If \(a_n=\alpha^n-\beta^n\) for \(n\geq 1\), then \[k=\dfrac{a_{10}-2a_8}{2a_9}\] Then find the remainder when \(k^{942}\) is divided by \(2014\).


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  • Something amazing happens when you add 1000 to the answer
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