A circular wire loop of radius \(R\) carries a total charge \(q\) distributed uniformly over its length. A small length \(x<<R\) of the wire is cut off. Find the electric field at the centre due to the remaining wire.

If the answer is in the form of \(\dfrac { qx }{ \alpha { \pi }^{ \beta }{ \varepsilon }_{ 0 }{ R }^{ \delta } } \), find \(\alpha +\beta +\delta \).

Assume the medium to be vacuum.

**Clarification:** \({ \varepsilon }_{ 0 }\) is the permittivity of free space.

×

Problem Loading...

Note Loading...

Set Loading...