# It's still zero!

**Electricity and Magnetism**Level 3

A circular wire loop of radius \(R\) carries a total charge \(q\) distributed uniformly over its length. A small length \(x<<R\) of the wire is cut off. Find the electric field at the centre due to the remaining wire.

If the answer is in the form of \(\dfrac { qx }{ \alpha { \pi }^{ \beta }{ \varepsilon }_{ 0 }{ R }^{ \delta } } \), find \(\alpha +\beta +\delta \).

Assume the medium to be vacuum.

**Clarification:** \({ \varepsilon }_{ 0 }\) is the permittivity of free space.

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