Break it off

Algebra Level 2

if \[(a-1)a(a+1)+(b-1)b(b+1)+(c-1)c(c+1)+........+(y-1)y(y+1)+(z-1)z(z+1)=0 \]

Find \[\frac{a^{3}+b^{3}+c^{3}+......+y^{3}+z^{3}}{a+b+c+.....+y+z}=\]

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