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∑r=125(3pr+2qr)\sum_{r=1}^{25}(3p_{r}+2q_{r})r=1∑25(3pr+2qr) Find the value of above expression if pr,qr(pr<qr)p_{r},q_{r} (p_{r}<q_{r})pr,qr(pr<qr) are the roots of x2−r2(r+1)x+r5=0x^{2}-r^{2}(r+1)x+r^{5}=0x2−r2(r+1)x+r5=0.
Try my set JEE ADVANCED 2016
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