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JEE Advanced 2016 (3)

Geometry Level 4

The centroid of the triangle formed by the feet of co-normal points on the curve $25x^{2}+25y^{2}-250x-300y+1525=(3x+4y-12)^{2}$ lies on the line

4x-3y+1=0

None of these

4x-3y-2=0

4x-3y+3=0

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by Shivam Jadhav

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