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The centroid of the triangle formed by the feet of co-normal points on the curve 25x2+25y2−250x−300y+1525=(3x+4y−12)225x^{2}+25y^{2}-250x-300y+1525=(3x+4y-12)^{2}25x2+25y2−250x−300y+1525=(3x+4y−12)2 lies on the line
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