JEE Inequalities Starter

Algebra Level 3

For a,b,c>0a,b,c>0 and a+b+c=6a+b+c=6. Find the minimum value of

(a+1b)2+(b+1c)2+(c+1a)2 \large \left (a+\frac{1}{b} \right )^{2}+ \left (b+\frac{1}{c} \right )^{2}+\left (c+\frac{1}{a} \right )^{2}

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