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Define the sequence tr t_r tr by
∑r=1ntr=n(n+1)(n+2)(n+3)8. \sum_{r=1}^n t_r = \dfrac{n(n+1)(n+2)(n+3)}8 .r=1∑ntr=8n(n+1)(n+2)(n+3).
Find limn→∞∑r=1n1tr \displaystyle \lim_{n\to\infty} \sum_{r=1}^n \dfrac1{t_r} n→∞limr=1∑ntr1.
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