JEE Main 2016 (13)

Algebra Level 5

If a,ba,b are the roots of x2+ωx12ω2=0x^{2}+\omega x-\frac{1}{2\omega ^{2}}=0, where ω\omega is a positive constant, find the minimum value of a4+b4a^{4}+b^{4}.


Try my set JEE Main 2016.
×

Problem Loading...

Note Loading...

Set Loading...