# JEE Main 2016 (5)

Algebra Level 5

If the equation $$z^{2}+z+\omega=0$$ has purely imaginary root and $$ω$$ lies on the circle $$|z|=1$$ and $$1+\omega+\omega'=\sqrt{A}$$. Find $$A$$

$$ω'$$ implies the complex conjugate of $$\omega$$.

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