JEE-Mains 2014 (1/30)

If \(X=\{ 4^n-3n-1 : n \in \mathbb{N}\}\) and \(Y=\{9(n-1): n \in \mathbb{N} \}\) , where \(\mathbb{N}\) is the set of natural numbers, then \(X \cup Y\) is equal to :

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