# JEE-Mains 2014 (1/30)

Discrete Mathematics Level 2

If $$X=\{ 4^n-3n-1 : n \in \mathbb{N}\}$$ and $$Y=\{9(n-1): n \in \mathbb{N} \}$$ , where $$\mathbb{N}$$ is the set of natural numbers, then $$X \cup Y$$ is equal to :

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