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JEE-Mains 2015 (10/30)

Calculus Level 3

\[\large \displaystyle \lim_{x \to 0} \dfrac{(1-\cos 2x)(3+\cos x)}{x \tan 4x}= \ ?\]

4 \[\frac{1}{2}\] 2 3

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by Sandeep Bhardwaj

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