JEE-Mains 2015 (11/30)

Calculus Level 3

\[\text{ Given : } g(x)= \begin{cases} k\sqrt{x+1} \quad, \quad 0 \leq x \leq 3 \\ mx+2 \quad , \quad 3<x \leq 5 \end{cases}\] If the function \(g(x)\) is differentiable, then the value of \(k+m\) is :

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