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JEE-Mains 2015 (14/30)

Calculus Level 3

The integral \(\displaystyle \int \dfrac{dx}{x^2(x^4+1)^{\frac{3}{4}}}\) equals :

\[-(x^4+1)^{\frac{1}{4}}+c\] \[-\left(\dfrac{x^4+1}{x^4}\right)^{\frac{1}{4}}+c\] \[(x^4+1)^{\frac{1}{4}}+c\] \[\left(\dfrac{x^4+1}{x^4}\right)^{\frac{1}{4}}+c\]

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by Sandeep Bhardwaj

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