JEE-Mains 2015 (14/30)

Calculus Level 3

The integral $\displaystyle \int \dfrac{dx}{x^2(x^4+1)^{\frac{3}{4}}}$ equals :

-(x^4+1)^{\frac{1}{4}}+c

-\left(\dfrac{x^4+1}{x^4}\right)^{\frac{1}{4}}+c

(x^4+1)^{\frac{1}{4}}+c

\left(\dfrac{x^4+1}{x^4}\right)^{\frac{1}{4}}+c

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