JEE-Mains 2015 (17/30)

Calculus Level 5

(xlogx)dydx+y=2xlogx,x1(x\log x)\frac{dy}{dx}+y=2x\log x, \quad x \geq 1
Let y(x)y(x) be the solution of the above differential equation, then y(e)y(e) is equal to :

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