JEE-Mains 2015 (23/30)

Geometry Level 3

The distance of the point (1,0,2)(1,0,2) from the point of intersection of the line x23=y+14=z212\dfrac{x-2}{3}=\dfrac{y+1}{4}=\dfrac{z-2}{12} and the plane xy+z=16x-y+z=16 is :

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