JEE-Mains 2015 (23/30)
Geometry
Level
3
The distance of the point \((1,0,2)\) from the point of intersection of the line \(\dfrac{x-2}{3}=\dfrac{y+1}{4}=\dfrac{z-2}{12}\) and the plane \(x-y+z=16\) is :
by
Sandeep Bhardwaj