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The distance of the point (1,0,2)(1,0,2)(1,0,2) from the point of intersection of the line x−23=y+14=z−212\dfrac{x-2}{3}=\dfrac{y+1}{4}=\dfrac{z-2}{12}3x−2=4y+1=12z−2 and the plane x−y+z=16x-y+z=16x−y+z=16 is :
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