Strange Cross Products

Geometry Level 2

Let a,b\vec{a},\vec{b} and c\vec{c} be three non-zero vectors such that no two of them are collinear and (a×b)×c=13bca(\vec{a} \times \vec{b}) \times \vec{c}=\frac{1}{3} |\vec{b}||\vec{c}| \vec{a}. If θ\theta is the angle between vectors b\vec{b} and c\vec{c}, then the value of sinθ\sin\theta is :

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