JEE maths#22

Calculus Level 4

If S=4123+5234+6345S = \dfrac{4}{1 \cdot 2 \cdot 3} + \dfrac{5}{2 \cdot 3 \cdot 4} + \dfrac{6}{3 \cdot 4 \cdot 5} \cdots till nn terms and S=K(2n+5)2(n+1)(n+2)S = K - \dfrac{(2n+5)}{2(n+1)(n+2)} , then find K K.


For more JEE problems try my set
×

Problem Loading...

Note Loading...

Set Loading...