# JEE Novice - (12)

Algebra Level 4

$\Large\displaystyle\sum_{i=1}^{2003} i^2 = (2003)(4007)(334)$

$\Large (1)(2003) + (2)(2002)+ (3)(2001) \dots (2003)(1) = (2003)(334)(x)$

Find the value of $$x$$.

This question is a part of JEE Novices.

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