JEE Novice - (22)

Algebra Level 3

\[\large \begin{cases} \dfrac{x+y}{1+z} & = & \dfrac{1-z+z^2}{x^2-xy+y^2} \\ \dfrac{x-y}{3-z} & = & \dfrac{z^2+3z+9}{x^2+xy+y^2} \end{cases}\]

If \(x,y,z\) satisfy the system of equations above, find the value of \(z^3-y^3\).


This question is a part of JEE Novices.
×

Problem Loading...

Note Loading...

Set Loading...