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12+14+16+18+110+112\Large \dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{6}+\dfrac{1}{8}+\dfrac{1}{10}+\dfrac{1}{12}21+41+61+81+101+121
Which terms must be removed from the above summation , so that the sum of the remaining terms becomes equal to 1?
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