JEE Novice - (25)

Algebra Level 2

$\Large \dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{6}+\dfrac{1}{8}+\dfrac{1}{10}+\dfrac{1}{12}$

Which terms must be removed from the above summation , so that the sum of the remaining terms becomes equal to 1?

\dfrac{1}{6} , \dfrac{1}{8}, \dfrac{1}{12}

\dfrac{1}{2} , \dfrac{1}{6} , \dfrac{1}{10}

\dfrac{1}{4} , \dfrac{1}{12}

\dfrac{1}{8} , \dfrac{1}{10}

\dfrac{1}{8} , \dfrac{1}{12}

\dfrac{1}{4} , \dfrac{1}{8}