JEE Quadratic #4

Geometry Level 4

y2(y26)+x28x+24=0y^{2}\big(y^{2}-6\big)+x^{2}-8x +24 =0

Given the above equation, if the minimum and maximum values of x2+y4x^{2}+y^{4} are mm and MM, respectively, then find the value of M2mM-2m.

×

Problem Loading...

Note Loading...

Set Loading...