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y2(y2−6)+x2−8x+24=0y^{2}\big(y^{2}-6\big)+x^{2}-8x +24 =0y2(y2−6)+x2−8x+24=0
Given the above equation, if the minimum and maximum values of x2+y4x^{2}+y^{4}x2+y4 are mmm and MMM, respectively, then find the value of M−2mM-2mM−2m.
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