# JEE Quadratic #4

Geometry Level 4

$y^{2}\big(y^{2}-6\big)+x^{2}-8x +24 =0$

Given the above equation, if the minimum and maximum values of $$x^{2}+y^{4}$$ are $$m$$ and $$M$$, respectively, then find the value of $$M-2m$$.

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