JEE Sequence And Series

A set of consecutive natural numbers from \(1\) to \( n\) are written and one number is removed from it. The Arithmetic Mean of the remaining numbers is found to be \(\frac{71}{2}\), then the sum of all possible value(s) of the number removed from the set is \(z\)..

Find the value of \(\lfloor \sqrt{z} \rfloor\).


This Problem is inspired from a JEE 2013 Problem

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