\[\cos(A-C)\cos(B)+\cos(2B)=0\] Then \(a^{2},b^{2} \text{ and }c^{2}\) are in-

**Clarification:** \(A,B \text{ and }C\) are angles of triangle, \(a,b \text{ and }c\) are sides opposite to angles \(A,B \text{ and } C\) respectively.

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