Just a reverse

Algebra Level 3

xa+yb+zc=2 \frac{x}{a} + \frac{y}{b} + \frac{z}{c} = \sqrt{2} ax+by+cz=0 \frac{a}{x} + \frac{b}{y} + \frac{c}{z} = 0 x2a2+y2b2+z2c2= ? \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = \ ?

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