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∑n=420(n−4)!(n)!\sum_{n=4}^{20} \frac{(n-4)!}{(n)!}∑n=420(n)!(n−4)!
If the result of the summation above can be written in form ab\frac{a}{b}ba for aaa and bbb are positive, coprime integers, find a+ba + ba+b
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