Just Integrate

Calculus Level 4

Let f(x)=sec(x)dx2cos(2x)1f(x) = \displaystyle\int \dfrac{\sec(x) \, dx}{2\cos(2x)-1}

Given that f(0)=1f(0) = 1, find the value of f(π12)f\left( \dfrac{ \pi }{12} \right).

Give your answer to 3 decimal places.

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